THE ART AND SCIENCE OF MATHEMATICS
Wednesday, September 28, 2005
The Fibonacci Sequence

As we all know, the Fibonacci numbers $\{F_n\}$ satisfy the recurrence relation

\begin{displaymath}
a_{n+2} = a_{n+1} + a_n ,
\end{displaymath} (1)

with $F_1=1$ and $F_2=1$. The Fibonacci numbers are not the only solutions to this recurrence relation; different choices for $a_1$ and $a_2$ will give different sequences.

Is there is a solution to this recurrence relation of the form

\begin{displaymath}
a_n = \lambda^{n-1}
\end{displaymath} (2)

for $n=1,2,\ldots$ Since we take $a_1=\lambda^0$, which we define to be one even if $\lambda=0$, the trivial solution $a_n=0^{n-1}$ does not solve equation (1).


Problems

  1. Find the nontrivial solutions $\lambda=\lambda_1$ and $\lambda=\lambda_2$ so that $a_n=\lambda^{n-1}$ satisfies equation (1).
  2. Show that $a_n=c \lambda^{n-1}$ solves (1) for any constant $c$, provided $\lambda=\lambda_1$ or $\lambda=\lambda_2$.
  3. Show that $a_n=c_1 \lambda_1^{n-1} + c_2 \lambda_2^{n-1}$ solves (1) for any constants $c_1$ and $c_2$.
  4. Can you find constants $c_1$ and $c_2$ such that the Fibonacci numbers $\{F_n\}$ are given by
    \begin{displaymath}
F_n = c_1 \lambda_1^{n-1} + c_2 \lambda_2^{n-1}
\end{displaymath} (3)

    for every $n$?
  5. Consider a rectangle with sides of length $x$ and $y$, where $x<y$ and $\frac{y}{x}$ is equal to $\Phi$. Remove a square with sides of length $x$ from the rectangle. Show that the ratio of the sides of the remaining rectangle is also equal to the golden ratio.


Further reading




John E Mitchell and David Isaacson
2005-09-28