Fibers are labeled by their numerical apertures. The numerical aperture takes into account not only the cone of acceptance, but the effect on that cone of different media outside the fiber. Let us consider once again the fiber with a core index n1=1.5 and a cladding index of n2=1.4.

We can find the cut-off angle θ0max by working backward from the point where light strikes the upper edge of the fiber. In order for total internal reflection (TIR) to occur, the angle at this edge must be greater than the critical angle:
θ1 > θc
θ'1 is defined as the angle the light makes with respect to the normal at the entrance (left side) of the fiber. Looking at the figure, we see that θ'1 and θ1 are complementary. Thus
θ'1 < 90 - θc.
Snell's law applies at the entrance to the fiber, so
n0 sin θ0 = n1 sin θ1 < n1 sin (90 - θc)
We can use some trig identities (click here for detailed calculation) to arrive at the result
| n0 sin θ0max = (n12 - n22)1/2 = NA |
The quantity on the lefthand side of the equation is called
the numerical aperture (NA) of the fiber. Notice that the
expression for NA on the lefthand side of the equation seems to depend
on the material outside the fiber, but the expression in the center of
the equation does not. Numerical aperture does
not depend
on the material outside the fiber but depends only on the indices of the
core and cladding of the fiber. If the fiber is placed in a material
other than air, the index
n0 will
indeed increase, but the cut-off angle θ0
will decrease to keep the product n0
sin θ0maxconstant.
If NA were really dependent upon the material outside of the fiber, it
would not be a very good way of categorizing fibers.
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