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If there is no resistance, then ALL of the charge
(energy stored) will "explode" from the capacitor
all at once. This is how a camera flash works. But if
you can control the release of that energy by channeling
the "flow of stored charge" (ie: current)
through a capacitor, the capacitor will take a lot longer
to become fully discharged. The light bulbs used in
the capacitance demonstration
serve as resistors in this way.
Another practical application of resistors and capacitors
in series is to keep a circuit energized in case of
a power failure. My clock radio will keep its time setting
even if I unplug it from the wall for as long as 15
seconds. Some telephone answering machines will likewise
keep your messages for a long time if the electricity
from the wall is interrupted.
The mathematics is not complicated, and simply uses
the relation that current, i = dq/DT
You perform the loop rule using V = iR for the resistors
and V = Q/C for the capacitor.
Then, take the time derivative of the whole equation,
where dq/DT becomes i.
Now you have a differential equation of i and DI/DT
Solving, you get an exponential relation:
Current at any time = (current at time zero) exp[-(t/RC)]
RC is known as the "Time Constant", governing
how fast the capacitor discharges.
(See the textbook, section 28-8 if you are interested
in the details.)
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